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When you claimed the Sun was radiating 239.7w/m^2, you were wrong?
I never made that claim..that is you being unable to read and comprehend what is being written...sorry I the board doesn't have a crayon function to allow us to communicate at your level...
[When you claimed the Sun was radiating at -18C, you were wrong?
Again.. I never made the claim...just more bullshit from the toddster...misunderstanding..misinterpreting...missing the boat...
CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
its actually a two fold denial.CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
its actually a two fold denial.CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
its actually a two fold denial.CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
its actually a two fold denial.CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
its actually a two fold denial.CO2 in the Earth’s atmosphere only absorbs IRR at around 15um. Wavelength is directly proportional to temperature and 15um occurs at -80C. CO2 can only emit IRR at the same 15um so it radiates very low energy photons at -80C.
Now some simple quantum physics. Electrons orbiting a molecule can only do so at specific orbital heights. The higher the orbit, the higher the energy and the “warmer” (temperature is a measure of the kinetic energy of a substance) the molecule. When a photon hits a molecule, if it has too much energy, enough is absorbed to boost an electron to the next higher orbit and the rest is immediately radiated away. Magnetic resonance of the field holding the electrons in orbit will determine if a photon will be absorbed or re-emitted.
If there isn’t enough energy to boost an electron to the next available slot in a higher orbit, the photon’s energy is immediately re-radiated leaving the molecule with the same kinetic energy (temperature) as before.
Radiation from a molecule at -80C therefore cannot provide enough energy in the form of photons, to warm molecules (by boosting electrons into higher, more energetic orbits) at -4C or above (seawater temperatures).
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length. A colder object can not warm a warmer object.
CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
its actually a two fold denial.CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
its actually a two fold denial.
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
I don't know how your magic force fields block "cooler photons".
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
I don't know how your magic force fields block "cooler photons".
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
Is not a photon a charged particle?Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
I don't know how your magic force fields block "cooler photons".
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
its actually a two fold denial.CO2 is incapable of warming sea water as its thermal layer (skin) can not be penetrated by a photon at -80C wave length.
Is that because of the covailent (sic) bonds creating the force field to divert the photons?
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
Is not a photon a charged particle?If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
I don't know how your magic force fields block "cooler photons".
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
Like not knowing that a photon is a charged particle?its actually a two fold denial.
The energy of the photon is too weak to penetrate just 10um and the bond at differing wavelengths. Ever skip a rock on water? same concept..
A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
He debates like a 5 year old...how much do you expect?....I don't think I have ever seen him actually put any thought into, or actually defend any idea since I have been here...one liners is as much as he is able to manage...I guess he knows if he says more than one sentence on any topic..his ignorance will be brought to front and center.
Is not a photon a charged particle?You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
I don't know how your magic force fields block "cooler photons".
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
Is not a photon a charged particle?
No.
Like not knowing that a photon is a charged particle?A photon from matter at 100K is never absorbed by matter at 101K, because the bond knows the temperature of the source and makes it skip away?
That might actually be worse than SSDD's smart photon claim.
Magnetic resonance is logarithmic, thus as the wavelength and energetic disparity grows more is reflected. Angle and speed also have a direct impact on the object entering the lake. The hardness of the surface that a photon must defeat to be absorbed depends on the size and strength of the magnetic field. If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface. (Or sea water)
If the photons wave is to big and slow it will bounce off the tighter and more energetic field, like a rock hitting a frozen surface.
We aren't talking about reflection, we're talking about the force field that you imagine detects the temperature of the photon emitter, magically, and then, magically, refuses the let a "cooler photon" strike the warmer material.
You don't know how EM works, do you? Frequency? Wavelength? Its no wonder you can not grasp the concept.
He debates like a 5 year old...how much do you expect?....I don't think I have ever seen him actually put any thought into, or actually defend any idea since I have been here...one liners is as much as he is able to manage...I guess he knows if he says more than one sentence on any topic..his ignorance will be brought to front and center.
Is not a photon a charged particle?I don't know how your magic force fields block "cooler photons".
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
Is not a photon a charged particle?
No.
Why don't you elaborate? This I got to hear!
A photon has a positive charge as does all energy matter. Is that to basic for you?Is not a photon a charged particle?
That is why you do not understand how EM fields deflect and protect. Without them the earth would have no atmosphere and the surface would be barren waste. I guess the sun doesn't produce photons.. Right? And a cooler object must accept everything thrown at it.... Right?
Earths own EM fields show exactly how molecules can do the same on a much smaller scale. As the disparity of frequencies becomes larger they reflect and redirect particles/energy. This is why we have a very narrow bandwidth, which ultimately reaches the surface of the earth.
That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
Is not a photon a charged particle?
No.
Why don't you elaborate? This I got to hear!
Zero charge. No charge. Is that too complex?
A photon has a positive charge as does all energy matter. Is that to basic for you?Is not a photon a charged particle?That is why you do not understand how EM fields deflect and protect.
Now maybe you can explain the difference between deflecting charged particles from the Sun and deflecting photons from the Sun?
Is not a photon a charged particle?
No.
Why don't you elaborate? This I got to hear!
Zero charge. No charge. Is that too complex?
