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I scroll past the bullshit to get to the entertainment.Now I have to wonder if you are even able to see these words on paper...is your subconscious even allowing you to read them?
so post up a link to observed empirical evidence from one of your scientists. just one. I'll wait.
Atmospheric gases only absorb some wavelengths of energy but are transparent to others. The absorption patterns of water vapor (blue peaks) and carbon dioxide (pink peaks) overlap in some wavelengths. Carbon dioxide is not as strong a greenhouse gas as water vapor, but it absorbs energy in longer wavelengths (12–15 micrometers) that water vapor does not, partially closing the "window" through which heat radiated by the surface would normally escape to space. (Illustration NASA, Robert Rohde)[19]
Greenhouse effect - Wikipedia
Obtuse denial. It must be a gift.
It is evidence of greenhouse gases absorbing IR. Evidence you appear to believe does not exist. It is a link to observed measured evidence, which you asked for, rather than the graphic demonstrating that evidence, which you refused as 'a model'. Forgotten already?and this proves what?
Ffs.
It is evidence of greenhouse gases absorbing IR. Evidence you appear to believe does not exist. It is a link to observed measured evidence, which you asked for, rather than the graphic demonstrating that evidence, which you refused as 'a model'. Forgotten already?and this proves what?
Ffs.
But it isn't evidence that absorption and emission of IR by said gasses equals warming...again...the addition of greenhouse gasses to the atmosphere increase the emissivity of the atmosphere...what happens to a thing's ability to cool itself when you increase its emissivity?
it also emits and hands it off on collisions. so what, it doesn't warm a damn thing, and that is what is being asked as observed measured evidence. and still you got crickets.It is evidence of greenhouse gases absorbing IR. Evidence you appear to believe does not exist. It is a link to observed measured evidence, which you asked for, rather than the graphic demonstrating that evidence, which you refused as 'a model'. Forgotten already?and this proves what?
Ffs.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Naw I’ll scream it to stupid fks like you all day long. See, you can’t prove it. And, I know you can’t! So, I play with your stupid ass to show others your stupidYou don't understand very much.Yep. Increasing the signal to noise ratio. The signal which is there already.
then why can't they read it with an instrument at ambient temperature? noise? I fking agree. the fact is it isn't there, it's just noise.
then why can't they read it with an instrument at ambient temperature? noise?
You don't understand very much.
Signal-to-noise ratio (abbreviated SNR or S/N) is a measure used in science and engineering that compares the level of a desired signal to the level of background noise. SNR is defined as the ratio of signal power to the noise power,
Signal-to-noise ratio - Wikipedia
I know energy doesn't move from cold to warm. It's more than you know.
I know energy doesn't move from cold to warm.
You'll already broadcast your confusion, no need to repeat your errors.
Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Naw I’ll scream it to stupid fks like you all day long. See, you can’t prove it. And, I know you can’t! So, I play with your stupid ass to show others your stupidYou don't understand very much.then why can't they read it with an instrument at ambient temperature? noise?
You don't understand very much.
Signal-to-noise ratio (abbreviated SNR or S/N) is a measure used in science and engineering that compares the level of a desired signal to the level of background noise. SNR is defined as the ratio of signal power to the noise power,
Signal-to-noise ratio - Wikipedia
I know energy doesn't move from cold to warm. It's more than you know.
I know energy doesn't move from cold to warm.
You'll already broadcast your confusion, no need to repeat your errors.
Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
I agree, the cooler object will absorb from the warmer object while the warmer object cools down to the temperature of the cooler object. Never said that didn't happen. I claim the cooler object doesn't make the warmer object warmer. I'm still waiting on that evidence.
It doesn't. no exchange of energy to it. none. The only flow is warm to cold. seems you haven't figured that out.However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Naw I’ll scream it to stupid fks like you all day long. See, you can’t prove it. And, I know you can’t! So, I play with your stupid ass to show others your stupidYou don't understand very much.
I know energy doesn't move from cold to warm. It's more than you know.
I know energy doesn't move from cold to warm.
You'll already broadcast your confusion, no need to repeat your errors.
Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
I agree, the cooler object will absorb from the warmer object while the warmer object cools down to the temperature of the cooler object. Never said that didn't happen. I claim the cooler object doesn't make the warmer object warmer. I'm still waiting on that evidence.
I claim the cooler object doesn't make the warmer object warmer.
The cooler object emits much less than the warmer object.
How would it make the warmer object warmer?
It doesn't. no exchange of energy to it. none. The only flow is warm to cold. seems you haven't figured that out.However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Naw I’ll scream it to stupid fks like you all day long. See, you can’t prove it. And, I know you can’t! So, I play with your stupid ass to show others your stupidI know energy doesn't move from cold to warm.
You'll already broadcast your confusion, no need to repeat your errors.
Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
I agree, the cooler object will absorb from the warmer object while the warmer object cools down to the temperature of the cooler object. Never said that didn't happen. I claim the cooler object doesn't make the warmer object warmer. I'm still waiting on that evidence.
I claim the cooler object doesn't make the warmer object warmer.
The cooler object emits much less than the warmer object.
How would it make the warmer object warmer?
Suprise!! For once I agree with every thing in your post. It's rather elementary, but agreeable.Ergo the warming...radaition is a very efficient mover of energy...if you want to cool a thing, you move energy away from it in the fastest possible mode...ie...radiation...cooling fins...etc...You increase an objects emissivity by making it a more efficient radiator therefore making cooling more efficient.
Your blanket analogy represents conduction..not radiation...if you lie on your bed in a cold room..you will radiate heat right on out of your body into the room...lay a blanket over yourself and you make conduction the main means of moving energy from the surface of your body...
So the IR from the earth surface heats up the air.
Solids and liquids are usually very good at producing a wide variety of radiation wavelengths from internal molecular collisions because there are many types of 'bonds' holding the matter together.
Gases are not like that. They only have certain clear cut wavelengths that they absorb or emit.
The Ideal Gas Laws operate under the assumption that all molecular collisions are elastic. That is not true. Sometimes energy is absorbed to excite a molecule, sometimes an excited molecule ADDS kinetic energy by relaxing. The overall effect is minimal for a local area but is noticeable when you have a temperature gradient.
The atmosphere can absorb as much CO2 specific radiation as the surface can produce BUT it can only lose to space the amount of CO2 radiation that can be internally produced by the cold, thin air where it stops getting reabsorbed by the next CO2 molecule.
Not at all...Convection is not radiation...There is no radiative greenhouse effect as described by climate science...the temperature of our atmosphere is due to convection of energy absorbed from the sun and pressure acting upon the atmosphere...
The models are wrong because they are based on a radiative greenhouse effect as described by climate science and that doesn't describe energy movement through the atmosphere.
Not at all...Convection is not radiation...There is no radiative greenhouse effect as described by climate science...the temperature of our atmosphere is due to convection of energy absorbed from the sun and pressure acting upon the atmosphere...
The models are wrong because they are based on a radiative greenhouse effect as described by climate science and that doesn't describe energy movement through the atmosphere.
If you think so, then which step is wrong?
- Black body radiation from the earth is absorbed by the GHGs in the atmosphere.
- That loss of EM energy to the GHGs is random vibrational energy.
- The vibrating GHG will most likely hit a random air molecule.
- Gain of random energy in a gas is thermal energy.
- That energy gain in the atmosphere must be equal to the EM energy loss.
- The conservation of energy requires the above.
You're wrongIt doesn't. no exchange of energy to it. none. The only flow is warm to cold. seems you haven't figured that out.However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Naw I’ll scream it to stupid fks like you all day long. See, you can’t prove it. And, I know you can’t! So, I play with your stupid ass to show others your stupid
Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
I agree, the cooler object will absorb from the warmer object while the warmer object cools down to the temperature of the cooler object. Never said that didn't happen. I claim the cooler object doesn't make the warmer object warmer. I'm still waiting on that evidence.
I claim the cooler object doesn't make the warmer object warmer.
The cooler object emits much less than the warmer object.
How would it make the warmer object warmer?
It doesn't.
I've never seen anyone argue it did.
no exchange of energy to it.
Of course there is. Matter above 0K emits, even if warmer matter is nearby.
The only flow is warm to cold.
You're wrong.
seems you haven't figured that out.
I figured out your confusion a long time ago.
So, you are agreeing that IR from the earth indirectly causes the atmosphere to heat.Simply add a #7 which states clearly that the primary means of energy movement through the troposphere is conduction and you are there...Will you then try to claim that back conduction is heating the surface of the earth?
.radaition is a very efficient mover of energy...if you want to cool a thing, you move energy away from it in the fastest possible mode.
You're wrongIt doesn't. no exchange of energy to it. none. The only flow is warm to cold. seems you haven't figured that out.However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature.Found a nice drawing for you.
However, even if the two objects are not in contact and there is no physical medium to carry heat, the two objects will still eventually reach a common temperature. This occurs because objects with a nonzero temperature release and absorb energy via electromagnetic radiation. This emitted energy is commonly called blackbody or thermal radiation.
https://imgv2-2-f.scribdassets.com/img/document/311173396/original/fcad163b42/1539883108?v=1
Two bodies that are at the same temperature stay in mutual thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[21][22] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[23]
Black-body radiation - Wikipedia
Radiative exchange equilibrium[edit]
Planck (1914, page 40)[4] refers to a condition of thermodynamic equilibrium, in which "any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other."
The term radiative exchange equilibrium can also be used to refer to two specified regions of space that exchange equal amounts of radiation by emission and absorption (even when the steady state is not one of thermodynamic equilibrium, but is one in which some sub-processes include net transport of matter or energy including radiation). Radiative exchange equilibrium is very nearly the same as Prevost's relative radiative equilibrium.
Radiative equilibrium - Wikipedia
I agree, the cooler object will absorb from the warmer object while the warmer object cools down to the temperature of the cooler object. Never said that didn't happen. I claim the cooler object doesn't make the warmer object warmer. I'm still waiting on that evidence.
I claim the cooler object doesn't make the warmer object warmer.
The cooler object emits much less than the warmer object.
How would it make the warmer object warmer?
It doesn't.
I've never seen anyone argue it did.
no exchange of energy to it.
Of course there is. Matter above 0K emits, even if warmer matter is nearby.
The only flow is warm to cold.
You're wrong.
seems you haven't figured that out.
I figured out your confusion a long time ago.
Prove it!
So, you are agreeing that IR from the earth indirectly causes the atmosphere to heat.Simply add a #7 which states clearly that the primary means of energy movement through the troposphere is conduction and you are there...Will you then try to claim that back conduction is heating the surface of the earth?
I don't understand why you say conduction is a primary means of energy movement when you said
.radaition is a very efficient mover of energy...if you want to cool a thing, you move energy away from it in the fastest possible mode.
Everyone knows air is very poor at conduction.
