here are emission curves for three different temps in the star range.
it is easy to see that each curve has almost the exact same range of wavelengths as the others, although the higher temps produce more radiation and the average wavelength is in a higher energy band.
this type of graph makes the second law of thermodynamics easy to understand when dealing with radiation. although the range is almost exactly the same for each temperature, the amount of radiation at any particular wavelength is always larger for the hotter object. this is why heat alway flows from warmer to cooler. if you subtract the graph of the cooler object from the warmer one you get a visual amount of radiation which is available to be transfered to the cooler object. note well that all three curves produce photons in the full range, with the exception of very few extra high photons at the very left side. a 500nm photon produced by any of the temps is indistinguishable from the others.
here is a graph for temps more likely to be found under earthly conditions. same basic shape, same relationship as to why heat flows one way, towards the cooler because the warmer object is always producing more radiation in every range.
are the earth's surface and atmosphere perfect black bodies? of course not. I reccomend Glickstein at WUWT (Google Image Result for http://wattsupwiththat.files.wordpress.com/2011/05/gw-heat-light-detail.jpg or the guy at Science of Doom (Google Image Result for http://scienceofdoom.files.wordpress.com/2012/01/goody-p4.png?w=500) depending on which blogs you read. better yet, read both sets of article. better still read the comments after the articles as well. and the other articles on the same subject by the authors. and more articles on the subject by different authors. etc, etc, etc, until you understand the basics, understand the differences according to which side is talking, and then make up your own mind.
For now just a short response, because I`m certain the AGW spammers will bury it with as much of their garbage which has zilch to do with what you just posted. There is nothing wrong with any of your statements in this post.
However:
If you just "eyeball" the emission curves then they appear more similar than they really are..
Look at the Y-axis "Relative Brightness" and note the wavelength where each curve peaks.
If you got a CAD drag that graph into a window and examine each curve a little bit closer:
The 350 nm peak of the 7500 K curve has a Rel.Br. which is 11 times higher than the 650 nm peak of the 4500 K curve.
It only takes a few mouse clicks with a CAD program and you get the integral for each curves.
The relation ship is the same as for the relative peak values.
But none of that takes into consideration what should be the third dimension, which is completely missing on that graph.
And that is the energy increase of photons as the wavelength gets shorter. You could draw in that line yourself .
A 350 nm photon carries ~ 1.9 times the energy of a 650 nm photon.
Plot that relationship on the Z-axis which is not on that graph and then you can cube the graph which the familiar E= proportional relation ship with T in fact does.
From that extrapolate down to 20 C and the 15 000 nanometer photons that CO2 "re-emits" or "back radiates" with each of these photons .Then cube that graph again and you will notice that the CO2 "back radiation" effect is as miniscule as a fly having a head on collision with a freight train going in the opposite direction.
Last not least be aware that this graph is for IDEAL black bodies in a theoretical IDEAL vacuum. Only under IDEAL condition can an object convert heat energy quantitatively into light with that spectral distribution.
In the real world a 30mW Laser 532 nanometers needed 250mW at 650 nm for equal brightness.
That's 8.3 times more power...way more than what it would take with an ideal black body for a wavelength spectral span of only 118 nanometers...which is only 1 tick unit increment on the X-axis on that 2 dimensional graph
I should paste in what the Siamese cat and "Saigon" buried yesterday within minutes after I posted it:
The distinguishing difference between the terms kinetic energy and thermal energy is that thermal energy is the mean energy of disordered, i.e. random, motion of the particles or the oscillations in the system. The conversion of energy of ordered motion to thermal energy results from collisions.
For gaseous systems, the factor f, the number of degrees of freedom, commonly has the value 3 in the case of the monatomic gas, 5 for many diatomic gases, and 7 for larger molecules at ambient temperatures. In general however, it is a function of the temperature of the system as internal modes of motion, vibration, or rotation become available in higher energy regimes
Today's narrow definition of heat in physics contrasts with its use in common language, in some engineering disciplines, and in the historical scientific development of thermodynamics
sqrt (3 * Kelvin * Blz. constant(1.3805*10^- 23 J/K) divided by molecular mass of air 28.9 g/mol (4.799*10^-26) =average V is 500 meters per second at 300 K.
When you heat a gas by 1 deg then the average molecular speed increases by almost 30 meters per second and expands in an open system as a consequence.
It does so against a 1 atm pressure and that means work was performed, consuming energy...which in turn is no longer available to produce it`s energy equivalent in photons
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