flacaltenn
Diamond Member
Here's an estimate as a sanity check.
Volume of the oceans: 1.3 * 10^9 km^3
Specific gravity of water: 1 kg/dm^3
This converts to 1.3 * 10^21 kg
Specific heat of water: deg C = 4.186 Joules / gram
Using an approximation of 10 * 10^22 Joules rise since 2000, this converts to a 0.32 deg C rise. That's easily measurable. In fact, the resolution of a thermometer that's specifically designed for this is probably 100 times that.
1st cut? OK.. Now take sea water specifically. and add the pressure effects.. Good luck with the "more than 700m" description from this "letter"..
Part of the problem here -- is to my knowledge --- a PAPER on this topic has never been written giving the details for review.. It was published as a TWO PAGE "letter".
Rather hard -- even IF you're in the field -- to critique something this SWEEPING from "a letter".. Wonder why these details are not worth sharing with the general science audience?
Why? He's pretty much buried you with basic calculations that you aren't capable of.
Prove him wrong. You take sea water specifically, add pressure effects.....
Good luck with that.
" buried me with basic calculations"??? Hardly.. If I didn't understand the problem, I wouldn't have asked for the corrections..
There isn't enough information in that tweet of a "paper" to make the proper calculations..