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No b***ch YOU'RE a shoe salesman at a mall. As is Todd the Hick.So Todd, are you and your other magic gas barking kook buddies trying to FIND OUT the NAME of the LAW of PHYSICS you don't even know the NAME of, that - you're claiming you understand so well, that you've discovered it says a
COLD nitrogen bath is a HEATER
and the
COLD
light blocking REFRIGERANTS
chilling not just the ROCK but the entire nitrogen BATH,
are the CORE of the MAGICAL COLD NITROGEN HEATER?
I'm noticing you're not even able to make that sweaty mouse hand of yours even bring you to TRY to answer even BASIC questions about your KOOK pseudo-science church.
Still no link?
That one is incoherent
I'm the radiation engineer and atmospheric chemist MOCKING your dumb b**ch @#$ for letting somebody tell you a cold nitrogen bath's a heater.
You're a dummy. GFY
Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
YEAH I SEE where this is GOIN: if a ROCK on the ground is FACING the SUN, it won't glow at ALL on that side, until it's HOTTER than the SUN.
Every time you speak, you demonstrate that you know even less than your previous comment suggested. You are talking about visible light. The light came from a source. What is the temperature of the source that lit the rock compared to the temperature of the surrounding area in which it is being viewed? Clearly you don't even have a high school level back ground in science...Hell, a 6th grader could figure that out. Any time you are speaking about visiblie light, you have to consider the temperature of the light source.
No? "I ain't clymmidie like yew caws yew dun look't in thuh big buk werds, an' squigglie t?"
Very ironic. Really, you should take your own advice.Learn that name calling in the absence of any coherent argument is the surest way to have people simply ignore what you say.
That is your whole game here with your discarding of 150 years of science, and your caustic responses in place of coherent arguments. (CMB is a resonance frequency??? Jeez)
Yank your chain if it gets you through life...I am asking for physical evidence that demonstrates that the statements of the physical laws are mistaken as you claim. You can't provide any such evidence and it frustrates you...to damned bad.
Actually, I'm not frustrated at all. You're the one who claims yew dun "look't in thuh big buk, and thairs powurf'l thangs cain't be undurstood by hardly nobodie but thim clymmidy'unz
PHYSICAL EVIDENCE? ROCKS LAYING ON THE GROUND EMITTING INFRARED TOWARD THE SUN isn't EVIDENCE to YOU?
LmfaO!!!!!
No? "I ain't clymmidie like yew caws yew dun look't in thuh big buk werds, an' squigglie t?"
Very ironic. Really, you should take your own advice.Learn that name calling in the absence of any coherent argument is the surest way to have people simply ignore what you say.
That is your whole game here with your discarding of 150 years of science, and your caustic responses in place of coherent arguments. (CMB is a resonance frequency??? Jeez)
Yank your chain if it gets you through life...I am asking for physical evidence that demonstrates that the statements of the physical laws are mistaken as you claim. You can't provide any such evidence and it frustrates you...to damned bad.
Actually, I'm not frustrated at all. You're the one who claims yew dun "look't in thuh big buk, and thairs powurf'l thangs cain't be undurstood by hardly nobodie but thim clymmidy'unz
PHYSICAL EVIDENCE? ROCKS LAYING ON THE GROUND EMITTING INFRARED TOWARD THE SUN isn't EVIDENCE to YOU?
LmfaO!!!!!
Do you understand that there is a difference between energy radiating towards a thing....and energy actally reaching that thing? Are you able to grasp that because of the distance we are away from the sun, the energy that reaches us is a mere fraction of the energy that is actually leaving the surface of the sun?
Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
YEAH I SEE where this is GOIN: if a ROCK on the ground is FACING the SUN, it won't glow at ALL on that side, until it's HOTTER than the SUN.
Every time you speak, you demonstrate that you know even less than your previous comment suggested. You are talking about visible light. The light came from a source. What is the temperature of the source that lit the rock compared to the temperature of the surrounding area in which it is being viewed? Clearly you don't even have a high school level back ground in science...Hell, a 6th grader could figure that out. Any time you are speaking about visiblie light, you have to consider the temperature of the light source.
Stop talking like you sustained a brain injury while fighting a deer to the death in the woods with antlers taped to your head.
I ASKED YOU, WHY INFRARED LIGHT IS GOING OUT OF THIS PLANET, TOWARD the SUN.
Don't PRETEND this is a DANCE OFF, TELL ME HOW LOWER-FREQUENCY LIGHT GLOWS OUT of a ROCK on the GROUND, toward the MUCH HOTTER SUN.
You insipid "signts uh dum-dum" class genius.
Guess we are done allen...I am not the sort to get any enjoyment out of poking a stick at a caged animal...or make fun of a child.
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
YEAH I SEE where this is GOIN: if a ROCK on the ground is FACING the SUN, it won't glow at ALL on that side, until it's HOTTER than the SUN.
Every time you speak, you demonstrate that you know even less than your previous comment suggested. You are talking about visible light. The light came from a source. What is the temperature of the source that lit the rock compared to the temperature of the surrounding area in which it is being viewed? Clearly you don't even have a high school level back ground in science...Hell, a 6th grader could figure that out. Any time you are speaking about visiblie light, you have to consider the temperature of the light source.
Stop talking like you sustained a brain injury while fighting a deer to the death in the woods with antlers taped to your head.
I ASKED YOU, WHY INFRARED LIGHT IS GOING OUT OF THIS PLANET, TOWARD the SUN.
Don't PRETEND this is a DANCE OFF, TELL ME HOW LOWER-FREQUENCY LIGHT GLOWS OUT of a ROCK on the GROUND, toward the MUCH HOTTER SUN.
You insipid "signts uh dum-dum" class genius.
Let me guess...you think the radiant energy reaching that rock is the same temperarure as it was when it left the surface of the sun....and that till the rock reaches a greater temperature than the sun which is so far away (never mind the inverse square law) it can't radiate if the second law of thermodynamics is actually true? Is that what you think?
Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
The filament is hot enough to "overcome the power of the incoming sunlight"?
Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
The filament is hot enough to "overcome the power of the incoming sunlight"?
Incoming sunlight is how many watts per meter? A filament at 5000 degrees is radiatinig how many watts per meter?
No b***ch YOU'RE a shoe salesman at a mall. As is Todd the Hick.So Todd, are you and your other magic gas barking kook buddies trying to FIND OUT the NAME of the LAW of PHYSICS you don't even know the NAME of, that - you're claiming you understand so well, that you've discovered it says a
COLD nitrogen bath is a HEATER
and the
COLD
light blocking REFRIGERANTS
chilling not just the ROCK but the entire nitrogen BATH,
are the CORE of the MAGICAL COLD NITROGEN HEATER?
I'm noticing you're not even able to make that sweaty mouse hand of yours even bring you to TRY to answer even BASIC questions about your KOOK pseudo-science church.
Still no link?
That one is incoherent
I'm the radiation engineer and atmospheric chemist MOCKING your dumb b**ch @#$ for letting somebody tell you a cold nitrogen bath's a heater.
You're a dummy. GFY
Do you have any idea what the connection might be between a cold nitrogen bath and air at ambient temperature? Any idea at all?
Hey.Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
The filament is hot enough to "overcome the power of the incoming sunlight"?
Incoming sunlight is how many watts per meter? A filament at 5000 degrees is radiatinig how many watts per meter?
No b***ch YOU'RE a shoe salesman at a mall. As is Todd the Hick.Still no link?
That one is incoherent
I'm the radiation engineer and atmospheric chemist MOCKING your dumb b**ch @#$ for letting somebody tell you a cold nitrogen bath's a heater.
You're a dummy. GFY
Do you have any idea what the connection might be between a cold nitrogen bath and air at ambient temperature? Any idea at all?
I don't know what he is referring to, no.
Hey.Second Law of Thermodynamics: It is not possible for heat to flow from a colder body to a warmer body without any work having been done to accomplish this flow. Energy will not flow spontaneously from a low temperature object to a higher temperature object.
Tell me Allen...what do you think that statement means with regard to energy from a cooler object moving towards a warmer object? Do you think the second law of thermodynamics is a rule of thumb or a physical law which actually describes the movement of energy?
You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
The filament is hot enough to "overcome the power of the incoming sunlight"?
Incoming sunlight is how many watts per meter? A filament at 5000 degrees is radiatinig how many watts per meter?
GO POINT your RED L.E.D. flashlight, at the SUN again, and come back and TELL us if it comes on in the daytime.
Take your cat outside and see if it's true that indeed, no heat leaves him headed toward the sun. It can't, because
CooLieTons, can't go toward things giving off
HoTTieToNS.
Yeah. Absolutely.
What if I point my infared laser toward the sun, will any light come out of the end of it?
The sun and nearly all it's light is way hotter than my laser, what happens to the laser light?
Does it just go toward the sun a little bit then veer off? LoL. It's lazed, it can't veer anywhere.
Does it go toward the sun then just stop in space, like the f**kin' Matrix?
Just hovering there like a hot chick in leather who's gonna kick the sun's ass,
but just not ever get any closer, because HoddiePhoties won't let CooliePHoties come near em?
"Dont come toward me!! EWww!! git BACK CooLie-Pho-Tie-Tons, I'm tellin the second Law!
I'm uh drizzlin HoTTieToNS, yew cain't tuche this!"
No b***ch YOU'RE a shoe salesman at a mall. As is Todd the Hick.That one is incoherent
I'm the radiation engineer and atmospheric chemist MOCKING your dumb b**ch @#$ for letting somebody tell you a cold nitrogen bath's a heater.
You're a dummy. GFY
Do you have any idea what the connection might be between a cold nitrogen bath and air at ambient temperature? Any idea at all?
I don't know what he is referring to, no.
I'm referring to YOU thinking a cold nitrogen bath is a MAGIC HEATER,
and that the COLD light blocking REFRIGERANTS in the bath,
are the CORE of the COLD NITROGEN HEATER.
Hey.You tell me, you're the one who thinks if you shine your flashlight at the sun, no light will come out.
Go outside, and point your flashlight at the sun. If no light comes out then sure enough, you're the physicist and I'm the guy whose degree in radiation engineering left me believing if I point my flashlight at the sun, some light will come out, when it won't.
And that when the ground heats up, no infrared energy will come out of it as long as the sun is in that direction.
An engineer...of any discipline would never eve propose such a stupid experiment and expect it to mean anything. Even the most fleeting though on the topic would tell you thant is is meaningless. Tell me allen...in watts per square meter, how much energy from the sun is reaching the ground? Now, consider the temperature of the filament in a flashlight bulb...it is somewhere between 2700 and 3700 degrees kelvin. that means the temperature of that filament is going to be something between 4500 degrees and 6200 degrees Fahrenheit. Now, since you claim to be an engineer, what is the output in watts per square meter for an element at a temperature of say 5000 degrees? Now compare the output of the flashlight to the power of the incoming solar radiation. See where this is going?
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
Again, no engineer, of any sort would have asked such a stupid assed question and thought that it would inivalidate the second law of thermodynamics.
Of course, that energy from the flashlight would never actually reach the sun, but it is easily enough to emit through the incoming radiation from the sun.
The filament is hot enough to "overcome the power of the incoming sunlight"?
Incoming sunlight is how many watts per meter? A filament at 5000 degrees is radiatinig how many watts per meter?
GO POINT your RED L.E.D. flashlight, at the SUN again, and come back and TELL us if it comes on in the daytime.
Take your cat outside and see if it's true that indeed, no heat leaves him headed toward the sun. It can't, because
CooLieTons, can't go toward things giving off
HoTTieToNS.
Yeah. Absolutely.
What if I point my infared laser toward the sun, will any light come out of the end of it?
The sun and nearly all it's light is way hotter than my laser, what happens to the laser light?
Does it just go toward the sun a little bit then veer off? LoL. It's lazed, it can't veer anywhere.
Does it go toward the sun then just stop in space, like the f**kin' Matrix?
Just hovering there like a hot chick in leather who's gonna kick the sun's ass,
but just not ever get any closer, because HoddiePhoties won't let CooliePHoties come near em?
"Dont come toward me!! EWww!! git BACK CooLie-Pho-Tie-Tons, I'm tellin the second Law!
I'm uh drizzlin HoTTieToNS, yew cain't tuche this!"
yes, your laser will emit towards the sun. It emits at a very discrete frequency/wavelength so a great deal depends on what that is. And if the photons from your laser make it out of the atmosphere, they could very well make it all the way to the sun.
