Wuwei
Gold Member
- Apr 18, 2015
- 5,196
- 1,083
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Back to your smart photons again.You don't seem to grasp the concept of no signal at all...you can't measure any discrete wavelength of energy with an instrument that is warmer than the radiator... That is because there is no energy moving from the radiator to a warmer instrument...A degraded signal would at least be a signal.....there is none.