Toddsterpatriot
Diamond Member
Another molecule and it has only a 4/10,000,000 of being absorbed by another CO2 molecule. Which means it has to hit a molecule that has a longer residency time, like water vapor, which actually warms it slightly and rises as it now cools before it is released to space at a much longer wave length that CO2 is helpless to prevent escape.CO2 does not warm so your conduction theory is wrong. The energy residency time of CO2 is less than 0.002ns Thus the energy does not reside in the molecule to warm it. It is expelled almost immediately. This is why they were counting on water vapor to warm faster and hold the energy that it can not trap.You think IR does not warm the air? Then which of these do you think are false?The fact is ian, that IR does not warm the air, so the fact that is absorbed by CO2 and other so called greenhouse gasses means nothing with regard to the temperature.
1. IR strikes and excites CO2.
2. CO2 transfers excitation energy to an air molecule via conduction.
The energy residency time of CO2 is less than 0.002ns Thus the energy does not reside in the molecule to warm it. It is expelled almost immediately.
Where does it go next?
Another molecule and it has only a 4/10,000,000 of being absorbed by another CO2 molecule.
You might want to recheck your math.
Any links you can provide explaining your "covailent bond" theory of photon repulsion would be appreciated.